cancel
Showing results for 
Search instead for 
Did you mean: 
Data Engineering
cancel
Showing results for 
Search instead for 
Did you mean: 

Is there a function similar to split_part, json_extract_scalar?

dulu
New Contributor III

I am using spark_sql version 3.2.1. Is there a function that can replace

split_part,

json_extract_scalar

are not?

3 REPLIES 3

Ankush
New Contributor II

pyspark.sql.functions.

get_json_object

(colpath)[source]

Extracts json object from a json string based on json path specified, and returns json string of the extracted json object. It will return null if the input json string is invalid.

Kaniz
Community Manager
Community Manager

Hi @Du Lu​, We haven’t heard from you since the last response from @Ankush Jadhao​​​, and I was checking back to see if his suggestions helped you.

Or else, If you have any solution, please share it with the community, as it can be helpful to others.

Also, Please don't forget to click on the "Select As Best" button whenever the information provided helps resolve your question.

dulu
New Contributor III

Thanks @Ankush Jadhao​  for answer, I tried but only returns the first result in the cell. They seem to only take the first character with the correct result. I need out put like the table below.

I have the following input:

hinh22 

I am looking for a way to split the characters in the item_order_detail column into 2 columns itemID and itemName. As below output table uses SQL function in databricks with spark_sql version 3.2.1.

hinh223 

Welcome to Databricks Community: Lets learn, network and celebrate together

Join our fast-growing data practitioner and expert community of 80K+ members, ready to discover, help and collaborate together while making meaningful connections. 

Click here to register and join today! 

Engage in exciting technical discussions, join a group with your peers and meet our Featured Members.