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01-30-2024 05:20 AM
This is my code here.
df = spark.createDataFrame([[1,1,2]], schema=['id','first_name','last_name'])
(df.write.format("jdbc")
.option("url", <jdbc-url>)
.option("dbtable","hive_metastore.default.test")
.option("driver", "com.databricks.client.jdbc.Driver")
.mode("overwrite")
# .saveAsTable("test")
.save()
)
The Error
An error occurred while calling o273.save.
: java.sql.SQLException: [Databricks][JDBCDriver](500051) ERROR processing query/statement. Error Code: 0, SQL state: 42601,
Query: CREATE TAB***, Error message from Server: org.apache.hive.service.cli.HiveSQLException:
Error running query: [PARSE_SYNTAX_ERROR]
org.apache.spark.sql.catalyst.parser.ParseException:
[PARSE_SYNTAX_ERROR] Syntax error at or near '\"id\"'.(line 1, pos 19)
== SQL ==
CREATE TABLE test (\"id\" BIGINT , \"first_name\" BIGINT , \"last_name\" BIGINT )
1 ACCEPTED SOLUTION
Accepted Solutions
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01-30-2024 07:11 AM
%scala
import org.apache.spark.sql.jdbc.{JdbcDialect, JdbcDialects}
JdbcDialects.registerDialect(new JdbcDialect() {
override
def canHandle(url: String): Boolean = url.toLowerCase.startsWith("jdbc:databricks:")
override
def quoteIdentifier(column: String): String = column
})
you need register a JDBC Spark dialect to remove quote in column name
2 REPLIES 2
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01-30-2024 07:11 AM
%scala
import org.apache.spark.sql.jdbc.{JdbcDialect, JdbcDialects}
JdbcDialects.registerDialect(new JdbcDialect() {
override
def canHandle(url: String): Boolean = url.toLowerCase.startsWith("jdbc:databricks:")
override
def quoteIdentifier(column: String): String = column
})
you need register a JDBC Spark dialect to remove quote in column name
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01-30-2024 11:35 AM - edited 01-30-2024 11:35 AM
Thanks, it worked!

