Get metadata of files present in a zip

[seeker]

I have a .zip file present on an ADLS path which contains multiple files of different formats. I want to get metadata of the files like file name, modification time present in it without unzipping it. I have a code which works for smaller zip but runs into memory issues for large zip files leading to job failures. Is there a way to handle this within pyspark itself?

[seeker]

Here is the code which i am using

def register_udf():
    def extract_file_metadata_from_zip(binary_content):
        metadata_list = []
        with io.BytesIO(binary_content) as bio:
            with zipfile.ZipFile(bio, "r") as zip_ref:
                for file_info in zip_ref.infolist():
                    file_name = file_info.filename
                    modification_time = datetime.datetime(*file_info.date_time)
                    metadata_list.append((file_name, modification_time))
        return metadata_list
    meta_schema = ArrayType(
        StructType(
            [
                StructField("file_name", StringType(), True),
                StructField("modification_time", TimestampType(), True),
            ]
        )
    )
    extract_metadata_udf = udf(extract_file_metadata_from_zip, meta_schema)
    return extract_metadata_udf
    
    
def get_last_modification_times(zip_file_path, expected_date, extract_metadata_udf):
    try:
        zip_file_df = (
            spark.read.format("binaryFile")
            .option("pathGlobFilter", "*.zip")
            .load(zip_file_path)
        )
        extracted_metadata_df = zip_file_df.withColumn(
            "file_metadata", extract_metadata_udf(col("content"))
        )
        exploded_metadata_df = extracted_metadata_df.select(
            explode("file_metadata").alias("metadata")
        )
        return exploded_metadata_df 
    except Exception as e:
        print("An error occurred: ", str(e))

[szymon_dybczak]

Hi @seeker ,

I'm afraid there is no easy way to do that in pyspark. Spark supports the following compression formats:

• bzip2
• deflate
• snappy
• lz4
• gzip

Thus, there is no native support for the zip format. And your solution will be slow, because you are using UDF which means it will apply this function on every row 😕

[Retired_mod]

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[Retired_mod]

Hi @seeker, There are only 2 ways I can think of to do it:

• Write a UDF.
• Write customized MapReduce logic instead of using Spark SQL.

But they are kind of the same. So I would say UDF is a good solution.