-
Removing the “Row” Node: When converting a DataFrame to XML, the default behaviour is to wrap each row in a <Row>
node. However, you want to remove this extra layer and directly nest the child elements under the root parent. We can achieve this using the scala-xml
library.
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Example Using RuleTransformer
: We’ll use the RuleTransformer
to transform the XML structure. Specifically, we’ll create a custom rule that removes the <Row>
node and moves its children to the root parent.
Here’s an example of how you can achieve this:
import scala.xml._
import scala.xml.transform._
val xmlWithRow: Elem =
<root>
<Row>
<name>Alice</name>
<age>30</age>
</Row>
<Row>
<name>Bob</name>
<age>25</age>
</Row>
</root>
class RemoveRowRule extends RewriteRule {
override def transform(node: Node😞 Seq[Node] = node match {
case Elem(_, "Row", _, _, children @ _*) => children
case other => other
}
def apply(xml: Node😞 Node = new RuleTransformer(this).transform(xml)
}
val transformedXml: Node = new RemoveRowRule().apply(xmlWithRow)
println(transformedXml)
In this example:
- We define a custom
RemoveRowRule
that matches <Row>
nodes and replaces them with their children.
- The
RuleTransformer
applies this rule to the entire XML structure.
- The resulting
transformedXml
will have the <Row>
nodes removed, and their children will be directly under the root <root>
node.
Feel free to adapt this example to your specific use case by replacing the sample XML with your actual data. Remember to adjust the rule to match your schema and nesting structure.
Remember that XML in Scala is immutable, so the transformation creates a new XML structure without modifying the original.
I hope this helps! Let me know if you have any further questions or need additional examples. 🌟